Standard+2.6-eh

Standard 2.6.a:Solving Polynomials using various methods.
Polynomial equations with degrees up to four can be solved exactly using algebraic methods, of which the quadratic formula is the simplest example. Polynomial equations with a degree of five or higher require numerical methods or special functions such as big radicals

Example Problems for Standard 2.6a
Below are two example problems. 2y 2 + 3y – 40 / y + 5 Divide y + 5 into 2y 2 + 3y get -2y 2 -10y then Subtract from 2y 2 + 3y you get -7y then you bring down the -40, Repeat the process. Divide -7y by y get -7. Multiply -7(y+5) = -7y -35 then subtract. The remainder is -5. Answer: 2y – 7 + -5 divided by y + 5.
 * Problem 1**

Simplify: __8x__ __3__ __+ 4x__ __2__ __– 12x__ 2x 2 **Divide each term by** **2x2** __8x__ __3__ + __4x__ __2__ - __12x__ 2x 2 2x 2 2x 2 4x 1 + 2x 0 – 6/x Use division rule for exponents. 4x + 2 – 6/x Answer.
 * Problem 2**

Podcast for Standard 2.6a
Below is a tutorial on understanding polynomial equations and how to solve the problems.